Відео

En que pais estan?

u are my legendary, doc linaries , i was one of ur student before and u write reference for me, now i was graduate, i miss u so much

realy❤❤❤❤❤

Thank you very much!!!

I wish professors would come and learn from you how to present their lectures to students. You make everything easy to understand. Thank you very much, Sir.

How do I update the firmware?

THIS IS AWESOME! I finally found someone that sounds like they're speaking english when they interpret these data graphs.

Excelente explicación, gracias.

Excellent tutorial

Thank you! I teach at UBCO and this was helpful. I've been teaching for 4 semesters and each time I have to re-learn how to upload the grades 😅

When I try to solve the equations I get empty brackets why?

Your videos are so well done, it's exciting me to learn about this again! Thanks for your contribution and fun style of presentation! (a fellow Canadian!)

Yes, just yes! This is how educational videos should be made. I love the whole atmosphere of this video so much! The background, the blues intro, the tone of your voice, ... It makes me less afraid of the difficulty and more eager to learn about it! Thanks a lot! This will definitely help me for my exams :)

Thank you professor

Sir your explanation is great

Sir,is there any book written by you on electronics, electrical, control system...or any pdf soft copy available written by you..

Great videos!

This guy talks sense with less BULLSHIT. He compresses AN ENTIRE SEMESTER to 40 minutes

you make me clear that i was not know the topic even i see many videos before thanks.

Thank you, very much Roli. I find myself using expand() quite often and being able to assign it to a user key is very helpful.👍

Awesome explanation! Love your videos

Boa noite!! Ótimo vídeo!! Parabéns!! Não sei se pode me ajudar. Estou com o emulador, mas quando calculo a integral indefinida de (2x/(X²+4) ela apresenta como resultado LN (X²+4) / 2, mas o correto é apenas LN (X²+4). Já tentei escrever (2x/(X^2+4), mas o único jeito que ela apresenta a resposta correta é quando digito a expressão (2x/(x * x + 4), que seria a mesma coisa. Assim o resultado é LN (x²+4). Será que na calculadora física esse erro também acontece? Valewwww

Thanks professor!

Thank you sir

I like your videos

I recently updated my HP Prime with the 2024 release of the firmware. It now shows an "S" value in the Triangle Solver. Can anyone tell me what that value measures or how it's computed? Thank you.

Thank you very much

Dear Professor, Apologies for the late comment, I just found and purchased a HP Prime G2 for my Engineering studies, and am very grateful for your videos. For this one, however, when I tried to solve for w using the exact steps you have mentioned, instead of nice numbers, I got some very strange, long results with _y and _x. Do you know why this may be the case and how it can be changed? (FYI I have tried again with the virtual emulator, and got the same result)

When I press check after writing this simple resistor program, the (physical G2) device returns a "syntax error". I'm stuck there.

how do you get a lower case j on the hp prime calculator. I can only see the capital J in orange. please respond. Thank you.

😇😇😇👍👍👍🙏🙏🙏 really good, great job.

Wonderful

Superb video, with a high density of information and the granularity to understand the idea behind the method you show. I like your approach to explain in such a "friendly advisor mode"!

So smooth video, I like your approach as a friendly advisor👌

The best teacher on UA-cam, on any subject; period.

First of all thank you Sir for sharing your knowledges. Second, someone solved the first problem? If yes here are my answers: S(Source) = 0.704 - j3.874 kVA S(Factory )= 1.346 - j3.7 kVA I considered 125V and 63A as peak values.

Mind blown! Really good explanation!

I like it!!

good wather comes from good source Excellent thank you

Dear Professor, Thank you for your channel. It is valuable. But I think I see a "bug" in the RR program. RETURN should not use the "()" to return value - using it, you return the complex number a real part :). I noticed that by a small mistake. I wanted to round the output to 2 digits, so I wrote RETURN(ROUND(r1*r2/(r1+r2)),2). I was surprised that the evaluation was x+2i. I made a mistake, and I realized output is a complex number. Now I have "RETURN ROUND(r1*r2/(r1+r2),2)", and it works perfectly.

Great video, I have just bought an HP Prime for my nephiew, he wants to study enginnering, so in my opinion this is a very good Xmas gift, I had an HP 48GX when I was studying engineering in the 90s, a great machine, expensive but worth every penny I paid for it, but, as always, you need to start by the basics and learn how to use it to get the full potencial of it, thanks for the video and merry Xmas (2023 :) )

Thank you very well done. I have used RPN so much and have almost forgot it, I can use it if I want, but at other times love the algebretic.

Great, thank you so much for all of the HP videos!

Very clear explanation.

Thanks for the video. I try to reproduce this with the April 2023 firmware and can't. Anyone else?

I studied physics,electrical engineering and computer engineering back in 1973 when the early computers looked like kitchen-refrigerators,huge and bulky enough to transport one computer in a pick-up truck,one at a time when molecular-alloys- made transistors were not in use,,,I am from the old-school ,at a time to get those three degrees would have taken only the brain of Albert Enstien to figure out,,,,.With modern internet,getting any university degree,is a"Piece of Cake",is a"Walk in the Park" and you still see some of these young students are bitching about how difficult it is to get a degree,,,Bunch of "Diamond-Spoon Fed Loose Lazy Asses with Bagle-Holes Shining Down Back Yonder".......Arash Sassani,Rasht,Iran.😅😅😅😅😅😅😅😅😅❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤ ❤😅😅😅😅😅😅😅😅😂

The best explanation I have ever seen by far of the design of a simple common emitter circuit.

Hi Prof.! I did the technic from 5:44 to find the anchor with a "high pass filter of order 2" but without success : I explain : from 2 high pass filter of order 1 (gain k1 , cut frequency = wo1) and (gain k2 , cut frequency = wo2) I get : k1 j w/wo1 k2 j w/wo2 ----------------- ------------------ 1 + j w/wo1 1 + j w/wo2 I get all gain = k1 * k2 and limit H(s) when w -> infinity => 20 log ( abs (H(infinity))) = 20 log abs (k1*k2) (it is verified with visual simulation) So : k1 s / wo1 k2 s / wo2 ----------------- ------------------ 1 + s / wo1 1 + s / wo2 k1 s k2 s ------------- -------------- wo1 + s wo2 + s and the total gain would be : k1 * k2 ---------------- wo1 * wo2 Can you tell me the wrong step ?

I used the KVL to list the system equation to get the I(s) expression, and found the importance of separating the "voltage part" and "impedance part" in equivalent models of capacitors and inductors, as I need to find the voltage polarities of all components. Thank you so much Sir.

Sir, Thank you so much for the great work. I finally understood complex number, Laplace transformation, and their application in real world, it's like finding the meaning of learning math. Your videos are priceless treasury for engineering students. BTW, for the voltage source with a concrete sinusoidal expression, it looks way easier to use phasor.